Students, please use the following LINK to watch a video about Solving Limits Graphically. Begin watching the video at the 2:15 time mark and stop watching the video at the 6:00 time mark.
After you have watched the video, each student is to work one problem from the assignment below, Solving Limits Graphically (see directions about which problem to solve), showing his/her basic understanding of evaluating limits graphically from the video. Please follow the directions of what you need to include in each post below.
Choosing a Problem
- If you are the first to post, select problem #1.
- If you are not the first student to post, look through the comments and choose the next problem that has yet to be solved, staying in numerical order.
What should I include in my posted comment?
- Indicate which problem number you solved and the solution to your problem.
- Share what you thought about the video and how you feel about learning limits this way.
- If you are unable to answer your problem, please post a question and I will assist you.
Solving Limits Graphically Assignment:
I have watched the video several times and have no clue. I can understand it on the video but not on the large graph because there is so much going on. I am going to guess the answer to number one, 3? I like the idea of learning on a video like this, but struggle because I cannot ask questions.
ReplyDeleteLet me know if I got it wrong and maybe you can give me a hint. Being an art major now and teaching language arts for ten years, math was never my strong area!
DeleteHelen...so sorry for the difficulty. I appreciate you taking the time to try to understand and apply. I know I was very specific, but I do hope to learn what best way to apply somethign like this to my subject area.
DeleteThe solution to #1 is -1. If you follow along the x-axis to the left of the origin to x = -5, you will see the curve below the x-axis and a point (-5, 3) above the x-axis. To best understand a limit, you want to know what is the curve approaching in terms of its y-value, not what it equals. If I asked you what y equals when x is -5 we would say 3, but if we asked what the curve approaches when x = -5, we would say -1.
I know I'm not staying in numerical order, but I am answering question #4 because it is the only one I'm really confident about! I think the answer is -2 because as you approach 2 from either direction the curve below is approaching -2. The video was helpful but, to be honest, I got a little help from my teenage son. I agree with Helen that it is difficult to solve with so many curves on the graph, but I do think that adding videos to blogs increase their usefulness.
ReplyDeleteAimee, thanks for your feedback. I know being real specific to my subject may make it more difficult for others in our class and as I have shared in another post, I wanted to test this idea for its effectiveness. Thanks for sharing why you went out of order. Good to hear you using your resources.
DeleteI am solving question #2, and I believe the answer is, DNE because as X approaches -3, nothing is approaching the y-axis. If my answer is correct, then I found the video segment to be pretty simple to understand. Even though it was pretty simplified compared to the questions listed here. (If my answer is incorrect though, I have to take that statement back.)
ReplyDeleteHeather, you have answered correctly. What is great is that you answered a problem that didn't have an exact example like that in the video. Thank you for participating and letting me try something more specific to my subject matter and to use this as a test to see its effectiveness.
DeleteThe answer to #3 is DNE since the limit doesn't approach a number from the left AND the right. The video was good, but I would assume honestly that someone who saw it for the first time and came to this problem might get confused with all the graphs. I have a math background, and used to seeing these types of problems, therefore wasn't too bad for me. I do believe the video is helpful, but maybe start with a more simple problem first and grow to this one. Enjoyed the video as a whole, it explained the concept very well!
ReplyDeleteChalandra, I appreciate the feedback. The problems posted in all honesty were for done with expediency, coming from assessment I have used. This does have difficulty for those without a math background. I chose this so I can see how effective it might be and the feedback I could received from other.
DeleteThis comment has been removed by the author.
ReplyDeleteThe answer to number 4 is -2 because the limit approaches x=2 from the left and the right at y= -2. The video was a good resource to use in learning this lesson. It was one of the clearest explanations I have seen for this topic, but I do have a good math background, so it was easy for me to understand.
ReplyDeleteThank you Felicia for your time and response. There are many great resources out there we can connect to Blogger. I do hope this is a great example of something you could try in your math class one day.
DeleteI have never been a fan of math so I am not sure if I am right, but I believe the answer to number 5 is 1 and -1.
ReplyDeleteKylee, thank you so much for participating. This level of math is taught towards the end of precalculus and is a staple in calculus. You are very close. The solutions you provided are for what we call one sided limits. The solutions is -1 when you approach x = 4 from the left and 1 from the right, therefore, the limit DNE when you approach x = 4 from both sides. Again, I appreciate your effort and time.
Delete